A wire of radius 0.7 cm carries a current of 125 A that is uniformly distributed over its cross-sectional area. Find the magnetic field B at a distance of 0.13 cm from the center of the wire.

Respuesta :

The magnetic field is the type of zone that receives magnetic force. It can have a strength of 0.00122 T.

Magnetic field

  • The magnetic impact on passing an electrical current, electromagnetic fields, and materials and devices is described by a magnetic force, which is a vector field.
  • A force perpendicular to both the charge's own velocity and the magnetic field acts on a moving charge in the field of magnetism.

Provided that,

radius, r = 0.7 cm = 0.007 m

current, I = 125 A

position considered, x = 0.13 cm = 0.0013

Formula of the magnetic field,

[tex]B=u_{0}Ix/4\pi r^{2}[/tex]

⇒[tex]B=4\pi* 10^{-7} *125 * 0.0013 / 4\pi (0.007)^{2}[/tex]

⇒[tex]B=0.00033[/tex] T

So, the value of the magnetic field = 0.00033 T

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