The mass of water produced is 5.58g.
The given reaction is a neutralization reaction. Since both acid and base are strong, so, they dissociate completely to form salt and water. Therefore the number of moles of acid, base, salt, and water are equivalent.
Step-1: Calculate the number of moles of [tex]H_{2}SO_{4}[/tex].
Given the mass of [tex]H_2SO_4[/tex] is 30g.
Molar mass of [tex]H_2SO_4[/tex] is 98g/mole.
Using the formula,
Number of moles= Mass/Molarmass
=30/98
=0.31 mole
Step-2: Mass of water
The molar mass of [tex]H_2O[/tex] is 18g.
The number of moles of [tex]H_2O[/tex] formed is 0.31 mole.
Using the formula,
Mass = Number of moles x Molar mass
Mass of [tex]H_2O[/tex] = 0.31 mole x 18g/ mole
=5.58g
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