Grogg has two bags of marbles, each of which contains some red marbles and some blue marbles (and no marbles of any other color). The ratio of red marbles to blue marbles in the first bag is 3:5. The ratio of red marbles to blue marbles in the second bag is 3:2. When the two bags of marbles are mixed together, the ratio of red marbles to blue marbles is 11:9. What is the ratio of the number of marbles in the first bag to the number of marbles in the second bag?

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Lanuel

The ratio of the number of marbles in the first bag to the number of marbles in the second bag is 2:7.

How to determine the required ratio?

First of all, we would assign the variables x and y to the marbles in the first and second bag respectively. Also, let F and S represents the first and second bag respectively.

For the first bag, we have:

Ratio = 3:5 = 3x:5x = 3x + 5x = 8x

For the first bag, we have:

Ratio = 3:2 = 3y:2y = 3y + 2y = 5y

Tabulating these values, we have:

                         Red        Blue

First bag              3x          5x

Second bag         3y          2y

The two red marbles = 3x + 3y.

The two blue marbles = 5x + 2y.

Next, we would write the ratio of the total red marbles to the total blue marbles:

Total red/Total blue = 11/9

(3x + 3y)/(5x + 2y) = 11/9

Cross-multiplying, we have:

27x + 27y = 55x + 22y

27y - 22y = 55x - 27x

5y = 28x

y = 28x/5

y = (28/5)x

y = 5.6x

Remember from the second bag, S = 5y:

S = 5(5.6x)

S = 28x.

Thus, the ratio of the number of marbles in the first bag to the number of marbles in the second bag is given by:

F/S = 8x/28x

F/S = 8/28

F/S = 2/7

F:S = 2:7.

Read more on ratio here: brainly.com/question/13513438

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