The ratio of the number of marbles in the first bag to the number of marbles in the second bag is 2:7.
First of all, we would assign the variables x and y to the marbles in the first and second bag respectively. Also, let F and S represents the first and second bag respectively.
For the first bag, we have:
Ratio = 3:5 = 3x:5x = 3x + 5x = 8x
For the first bag, we have:
Ratio = 3:2 = 3y:2y = 3y + 2y = 5y
Tabulating these values, we have:
Red Blue
First bag 3x 5x
Second bag 3y 2y
The two red marbles = 3x + 3y.
The two blue marbles = 5x + 2y.
Next, we would write the ratio of the total red marbles to the total blue marbles:
Total red/Total blue = 11/9
(3x + 3y)/(5x + 2y) = 11/9
Cross-multiplying, we have:
27x + 27y = 55x + 22y
27y - 22y = 55x - 27x
5y = 28x
y = 28x/5
y = (28/5)x
y = 5.6x
Remember from the second bag, S = 5y:
S = 5(5.6x)
S = 28x.
Thus, the ratio of the number of marbles in the first bag to the number of marbles in the second bag is given by:
F/S = 8x/28x
F/S = 8/28
F/S = 2/7
F:S = 2:7.
Read more on ratio here: brainly.com/question/13513438
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