The engine of a 1560-kg automobile has a power rating of 75 kW. Determine the time required to accelerate this car from rest to a speed of 100 km/h at full power on a level road. Is your answer realistic

Respuesta :

The time required to accelerate this car from rest to a speed of 100 km/h at full power on a level road is 7.73 seconds.

Mass of the engine = 1500 kg

Power rating = 75 kW = 75,000 W

Final speed = 100 km/hr =  = 27.78 m/s

v₁ = 0

Power = Work done ÷ Time

Work done = Final energy - Initial energy

=1/2 x 1560 x 27.78^2 = 1/2 x 1560 x 0^2\

= 578703.72 J

Thus,

75,000 = 578703.70 ÷ time=7.72 seconds.

Work is done every time a force moves something over a distance. By multiplying the force by the distance traveled in the direction of the force, you can calculate the energy transferred or the work done. Energy transmitted = work completed = force x distance traveled in the direction of the force.

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