The current in the second wire is 1.37 A.
The current in the second wire is calculated from the magnetic force between the two wires.
F/L = (μI₁I₂)/(2πr)
where;
μI₁I₂ = (F/L 2πr)
I₂ = ((F/L 2πr) / (μI₁)
I₂ = (7.7 x ⁻⁵ x 2π x 0.082)/(4π x 10⁻⁷ x 23)
I₂ = 1.37 A
Thus, the current in the second wire is 1.37 A.
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