By using trigonometric properties, we will see that:
tan(x) = 3/4.
Remember that the sine of the difference is:
sin(a - b) = sin(a)*cos(b) - sin(b)*cos(a).
Here we have:
sin(90° -x ) = 0.8
Expanding the sine:
sin(90° - x) = sin(90°)*cos(x) - sin(x)*cos(90°)
We know that:
sin(90°) = 1 and cos(90°) = 0, then:
sin(90° - x) = sin(90°)*cos(x) - sin(x)*cos(90°) = cos(x).
Then we have:
cos(x) = 0.8
And we want to find the tangent of x, which is:
[tex]tan(x) = \frac{sin(x)}{cos(x)}[/tex]
We already know that cos(x) = 0.8
Now, remember that:
[tex]sin(x)^2 + cos^2(x) = 1\\\\sin(x) = \sqrt{1 - cos^2(x)} \\[/tex]
Because x is an acute angle, sin(x) > 0, that is why we choose the positive root.
Replacing cos(x) we get:
[tex]sin(x) = \sqrt{1 - 0.8^2} = \sqrt{1 - 0.64} = \sqrt{0.36} = 0.6[/tex]
Then the tangent of x is:
[tex]tan(x) = \frac{0.6}{0.8} = \frac{6}{10}*\frac{10}{8} = 6/8 = 3/4[/tex]
If you want to learn more about trigonometric functions:
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