The magnitude of electric field inside the solid at a distance of 9.50cm from the center of the cavity is 6.5 x 10⁵ N/C.
V = ⁴/₃π(R³ - r³)
V = ⁴/₃π (0.092³ - 0.0655³)
V = 2.085 x 10⁻³ m³
Q = Vσ
where;
Q = 2.085 x 10⁻³ m³ x 7.35 x 10⁻⁴ C/m³
Q = 1.53 x 10⁻⁶ C
E = kQ/R²
E₁ = (9 x 10⁹ x 1.53 x 10⁻⁶)/(0.092)²
E₁ = 1.627 x 10⁶ N/C
E₂ = (9 x 10⁹ x 2.14 x 10⁻⁶)/(0.092)²
E₂ = 2.276 x 10⁶ N/C
Electric field inside the solid at a distance of 9.50cm from the center of the cavity;
E = E₂ - E₁
E = 2.276 x 10⁶ N/C - 1.627 x 10⁶ N/C
E = 6.5 x 10⁵ N/C
Thus, the magnitude of electric field inside the solid at a distance of 9.50cm from the center of the cavity is 6.5 x 10⁵ N/C.
Complete question:
A point charge of -2.14uC is located in the center of a spherical cavity of radius 6.55cm inside an insulating spherical charged solid. The charge density in the solid is 7.35×10−4 C/m^3.
a) Calculate the magnitude of the electric field inside the solid at a distance of 9.20cm from the center of the cavity.
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