Respuesta :

The grams of agarose that are weighed out are 6 g.

The concentration of a solution is expressed in a number of ways like molarity, molality, normality. It is also expressed as w/v, w/w, and v/v.

In w/v, the w represents the weight of the solute and v is the volume of the solution.

w/v = Mass of the solute/volume of the solution

Calculations:

It is given that w/v is 1.2%. This means that 1.2 g of agarose is present in 100 mL of the solution or 1.2 g/100 mL.

The weight of agarose present in 500 mL of the solution is calculated as:

Mass of agarose = (1.2 g/100 mL) x 500 mL

= 6 g

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