A 10-kg ring with outer radius 1.5 m and inner radius 1.2 m is placed snuggly around a solid sphere with mass 8.0 kg and radius 1.2 m. The combination rotates about the axis of the cylinder. What is the rotational inertia of the combination

Respuesta :

The rotational inertia of the combination is 21.5kg m2

Given that mass of ring = 10kg , outer radius 1.5 m and   inner radius 1.2 m

Radius of ring = ½(1.5+1.2) =1.35m

Mass of solid sphere=8kg

Radius of sphere =1.2m

A combination rotational inertia of ring and solid sphere is addiction of rotation inertia of ring and solid sphere

Rotational inertia of ring Ir=MR^2

Rotational inertia of solid sphere Is=2/5MR^2

Combination rotational inertia of ring and solid sphere

I=Ir+Is

=M1R^2+2/5M2R^2

=(10)(1.3^2)+⅖(8)(1.2^2)

=16.9+4.608

=21.5kg m2

Hence the rotational inertia of the combination is 21.5kg/m^2

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