The car will skid at 80m
As we know that In mechanics, acceleration is the rate of change of the velocity of an object with respect to time.
It is a vector quantity
The velocity is the distance covered by an object per unit time
Given
Initial velocity (u) = 15m/s
Final Velocity (v) = 0m/s
Distance (s) = 20 m
Deceleration (a) =?
Now we know that ,
v² = u² + 2as
Substituting the value
0² = 15² + (2)*(a)*(20)
0 = 225 + 40a
Collecting the like terms
0 – 235 = 40a
–225 = 40a
To find the value of a divide both side 40
a = –225 / 50
a = –5.625 m/s²
Determination of the distance
Deceleration (a) = –5.625 m/s²
Initial velocity (u) = 30 m/s
Final velocity (v) = 0 m/s
Distance (s) =?
v² = u² + 2as
0² = 30² +(2 × –5.625 × s)
0 = 900 – 11.25s
Collecting like terms
0 – 900 = –11.25s
–900 = –11.25s
To find the value of s divide both side by –11.25
s = –900 / –11.25
s = 80 m
Hence the car will skid 80 m
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