[tex]P(490 < X < 560)[/tex]= 0.3133
Given: μ = 560
σ = 90
To find: P (490 < X < 560)
Normal distributions are symmetric, unimodal, and asymptotic. A normal distribution is determined by two parameters the mean and the variance. A normal distribution with a mean of 0 and a standard deviation of 1 is called a standard normal distribution. It's always easy to solve questions in terms to standard normal
Hence, converting normal distribution to standard normal gives:
P(490 < X < 560) = [tex]P(\frac{560-560}{90}[/tex]≤ [tex]\frac{X-\mu}{\sigma} < \frac{640-560}{90})[/tex]
= P(0 ≤ Z < 0.888)
= P (z<0.89) - P(z ≤ 0)
Using standard normal table,
= 0.8133 - 0.5
P(490 < X < 560) = 0.3133
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