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A 120-milliliter mixture of Chemical X and water contained 40 percent Chemical X. A part of the mixture was removed and replaced with an equal quantity of water. If the resulting mixture contained 10 percent Chemical X, what is the volume of the mixture that was removed

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barmansuraj489

The volume of the mixture that was removed is 90ml

Given that chemical percentage present in 120 ml of mixture = 40%

and resulting mixture contained 10% of Chemical X = 120 * 0.1 = 12ml

Volume is the quantity of three-dimensional space occupied by a liquid, solid, or gas. Common units used to express volume include liters, cubic meters, gallons, milliliters, teaspoons, and ounces, though many other units exist.

Let us assume that  y be the volume of mixture removed

Therefore, we can re-write the equation as

0.4(120 - y) = 12

y = 90ml

Hence, 90ml was removed from the mixture

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