The velocity of the cart at the bottom of the ramp is 6.42m/s
Given that 40N cart slides from rest down a rough 6.0 m long ramp and the degree given is 30 and the friction force given is 6.0N
We need to find the velocity of the cart at the bottom of the ramp
One of two types of energy is known as potential energy and is the latent energy present in an item at rest.
According to the rule of conservation of energy, energy can only be transformed from one form of energy to another and cannot be generated or destroyed.
Potential energy of the crate at the top =40N×6sin30°m=120J
Energy lost due to friction =6N×6m=36J
Let the speed of the crate at the bottom be v.
Applying the law of conservation of energy,
120−36=0.5×(40/g)×v2
Therefore,
v=6.42m/s
Hence the velocity of cart at the bottom of the ramp is 6.42m/s
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