Mean (m) = 498
Standard deviation (σ) = 12
Sample size (n) = 86
The probability that the sample mean would differ from Population mean by less than 494.7 watts
P(m - s < Z < m + s)
P(498-494.7 < Z < 498+ 494.7)
Using the Z formula :
Zscore = (x - m) / (σ/√n)
x = 498 - 494.7 = 3.3 , x = 498 + 494.7 = 992.7
Z = (3.3 - 498) / (12/√86) = -383.48
P(Z < -383.48)
Z = (992.7 - 498 ) / (12/√86) = 383.48
P(Z<383.48)
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