The fall in the level of oil is 1.4147 cm when the total volume of oil consumed is 1 liter.
We assume the drop in the level of water to be d cm.
Since the container is cylindrical in shape, its volume is given as:
V = πr²h, where V is the volume, r is the radius, and h is the height.
In the question, we are given that the diameter of the can is 30 cm.
Hence its radius = 30/2 = 15 cm.
The capacity of the container is given to be 30 liters or 30*1000 = 30000 cm³.
The volume of the oil used = 1 liter or 1*1000 = 1000 cm³.
Thus, substituting V = 1000, r = 15, and h = d, in the formula of the volume, V = πr²h, we get:
1000 = π(15)²(d),
or, d = 1000/(225π) = 1.4147.
Thus, the fall in the water level is 1.4147 cm.
Therefore, the fall in the level of oil is 1.4147 cm when the total volume of oil consumed is 1 liter.
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