A circus is composed of acrobats, ballerinas, clowns, and dogs. The number of acrobats and ballerinas, minus the number of clowns, is one fewer than the number of dogs. Twice the combined number of acrobats and ballerinas is five more than three times the number of clowns. If the number of dogs is one more than the number of clowns, how many people and animals belong to the circus

Respuesta :

If we make appropriate equation then we can find that there are 21 people and animals belong to the circus.

Given The number of acrobats and ballerinas, minus the number of clowns, is one fewer than the number of dogs. Double the combined number of acrobats and ballerinas is five more than three times the number of clowns.

We have to find total people and animals belong to the circus.

An equation is relationship between variables that are expressed in equal to form. It is solved to find the variables in equal to form Equations of two variables look like ax+ by=c.

let the number of acrobats be x, ballerinas be y, clowns be z, clowns be u.

According to given information in question the equations are:

x+ y-z=u-1-----------------------1

2(x+ y)=3z+5-------------------2

u=z+1----------------------------3

Put the value of u from 3 in 1

x+y- z=z+1-1

x+y-2z=0

from 2

z=2x+2y-5/3

put the value of z in x+y-2z=0

x+y-2(2x+2y-5/3)=0

-x-y+10=0

x+ y=10-------------------------4

put put the value of x+y=10 in 1

10-z=u-1

u+z=11-----------------------------5

solving 3

u-z=1------------------------6

Now add 5&6

u+z+u-z=11+12

2u=12

u=6

Put the value of u in 6

6-z=1

z=5

From above we get x+y=10, u=6, z=5

Add all three we get the total number of people and animals belong to circus.

x+y+u+z=10+6+5

=21

Hence there are total 21 people and animals belong to the circus.

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