11 A is the amount of current that crosses the wire.
According to Ohm's law,
If all other physical parameters and temperatures remain constant, the voltage across a conductor is directly proportional to the current flowing through it.
V ∝ I
V= IR where,
V = Voltage across a conductor
I = Current flowing through the conductor
R= Resistance and also known as constant of proportionality
Given,
Resistance of wire(R) = 10 ohms
Voltage applied(V) = 110V
Current(I) = ?
According to the formula
110V = I × 10Ω
I = 110/10 = 11 A
Hence, current intensity of 11 A crosses a wire of 10 ohms if the voltage applied to the extremes of the wire is 110 V
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