What is the value of the current intensity that crosses a wire of 10 ohms if the voltage applied to the extremes of the wire is 110 V

Respuesta :

11 A is the amount of current that crosses the wire.

According to Ohm's law,

If all other physical parameters and temperatures remain constant, the voltage across a conductor is directly proportional to the current flowing through it.

V ∝ I

V= IR where,

V = Voltage across a conductor

I = Current flowing through the conductor

R= Resistance and also known as constant of proportionality

Given,

Resistance of wire(R)  = 10 ohms

Voltage applied(V) = 110V

Current(I) = ?

According to the formula

110V  = I × 10Ω

I = 110/10 = 11 A

Hence, current intensity  of 11 A crosses a wire of 10 ohms if the voltage applied to the extremes of the wire is 110 V

Learn more about Ohm's law here https://brainly.com/question/14296509

#SPJ4