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The combustion of glucose, c6 h12 o6 (s), produces carbon dioxide, co2 (g), and water, h2 o(g), according to the equation below. upper c subscript 6 upper h subscript 12 upper o subscript 6 (s) plus 6 upper o subscript 2 (g) right arrow 6 upper c upper o subscript 2 (g) plus 6 upper h subscript 2 upper o (l). the enthalpy of the reaction is –2,840 kj. what is the heat of combustion, per mole, of glucose?

Respuesta :

The heat of combustion per mol of the glucose is 2840 kJ.

A reaction that involves the burning of a compound in the presence of air or oxygen is called combustion. In the absence of oxygen combustion of a compound cannot take place.

It is given that the combustion of glucose produces carbon dioxide and water. The balanced chemical reaction for the given process is expressed as:

C6H12O6 (s) + 6O2 (g) ------> 6CO2 (g) + 6H2O (l)

The energy released from this reaction is -2840 kJ. The above equation clearly shows that 1 mol of glucose is used during the reaction and the energy produced is -2840 kJ.

Therefore, the heat of combustion per mol of the glucose is 2840 kJ.

Learn more about combustion here:

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