Find a39 of the arithmetic sequence given a1 = -28 and d = -4.
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A. -104
B. -106
C. 8
D. -180
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Hello !

[tex]a_{n} = a_{1} + (n - 1) \times d[/tex]

[tex]a_{39} = - 28 + (39 - 1) \times ( - 4) = - 28 + 38 \times ( - 4) = - 180[/tex]

The required a39 of the arithmetic sequence is -180.


Given that,
To find a39 of the arithmetic sequence given a1 = -28 and d = - 4.

What is arithmetic progression?

Arithmetic progression is the series of numbers that have common differences between adjacent values.

What is geometric progression?

Geometric progression is a sequence of series whose ratio with adjacent values remains the same.

The nth term of an arithmetic sequence is given as
an = a1 + (n - 1) * d
for term n = 39
a39 = -28 + (39 - 1) * -8
a39 = -28 - 152
a39 = - 180

Thus, the required a39 of the arithmetic sequence is -180.


Learn more about arithmetic progression here: https://brainly.com/question/20334860
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