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Taking into account the reaction stoichiometry, 108 grams of HCl form 131.70 grams of AlCl₃.

Reaction stoichiometry

In first place, the balanced reaction is:

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Al: 2 moles
  • HCl: 6 moles
  • AlCl₃: 2 moles
  • H₂: 3 moles

The molar mass of the compounds is:

  • Al: 27 g/mole
  • HCl: 36.45 g/mole
  • AlCl₃: 133.35 g/mole
  • H₂: 2 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Al: 2 moles ×27 g/mole= 54 grams
  • HCl: 6 moles ×36.45 g/mole= 218.7 grams
  • AlCl₃: 2 moles ×133.35 g/mole= 266.7 grams
  • H₂: 3 moles ×2 g/mole= 6 grams

Mass of AlCl₃ formed

The following rule of three can be applied: if by reaction stoichiometry 218.7 grams of HCl form 266.7 grams of AlCl₃, 108 grams of HCl form how much mass of AlCl₃?

[tex]mass of AlCl_{3} =\frac{108 grams of HClx266.7 grams of AlCl_{3}}{218.7 grams of HCl}[/tex]

mass of AlCl₃= 131.70 grams

Then, 108 grams of HCl form 131.70 grams of AlCl₃.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

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