Answer:
- [tex]\boldsymbol{\rm{y-2=\dfrac{3}{2}(x+1)}}[/tex], or D
Step-by-step explanation:
Hello
If a line's equation has the form [tex]\boldsymbol{\rm{y-y1=m(x-x1)}}[/tex], then it's considered to be in point-slope form.
In that formula,
- [tex]\boldsymbol{\rm{y1}}[/tex] is the y co-ordinate (2nd co-ordinate) of the point (here it's given as 2)
- [tex]\boldsymbol{\rm{m}}[/tex] is the slope, here it's 3/2
- [tex]\boldsymbol{\rm {x1}}[/tex] is the x co-ordinate (the first co-ordinate) of the point.
Now you know why this equation is called point-slope form!
Now that we're familiar with the equation, let's plug in the information that's given to us...
[tex]\boldsymbol{\rm{y-2=\displaystyle\frac{3}{2}(x-(-1)}}[/tex] | simplify
[tex]\boldsymbol{\rm{y-2=\displaystyle\frac{3}{2}(x+1)}}[/tex]
[tex]\pmb{\tt{done~!!}}[/tex]
[tex]\orange\hspace{300pt}\above3[/tex]
