From the reaction, the volume of the oxygen required is 89.6 L.
The term stoichiometry has to do with the process by which the mass of reactants or products in a reaction is obtained from the balanced reaction equation.
In this case, the balanced reaction is equation is;
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Number of moles of CO2 = 88.0 g/44 g/mol = 2 moles
2 moles of O2 produced 1 mole of CO2
x moles of O2 produces 2 moles of CO2
X = 4 moles
1 mole of oxygen occupies 22.4 L hence 4 moles of oxygen occupies 4 * 22.4 L = 89.6 L
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