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A beekeeper’s hives are making honey at a constant rate. The profit from honey can be represented by the equation

P(t) = -16t2 + 2050t + 150, where t is the time in days and P(t) is the profit the beekeeper receives. After how many days should she harvest her honey to maximize profit?

Respuesta :

Using the vertex of a quadratic function, she should harvest her honey after 64 days to maximize profit.

What is the vertex of a quadratic equation?

A quadratic equation is modeled by:

[tex]y = ax^2 + bx + c[/tex]

The vertex is given by:

[tex](x_v, y_v)[/tex]

In which:

  • [tex]x_v = -\frac{b}{2a}[/tex]
  • [tex]y_v = -\frac{b^2 - 4ac}{4a}[/tex]

Considering the coefficient a, we have that:

  • If a < 0, the vertex is a maximum point.
  • If a > 0, the vertex is a minimum point.

The profit function is given as follows:

P(t) = -16t² + 2050t + 150.

The coefficients are a = -16 < 0, b = 2050, c = 150, hence the t-value of the vertex is:

[tex]t_v = -\frac{b}{2a} = -\frac{2050}{-32} = 64[/tex]

Hence she should harvest her honey after 64 days to maximize profit.

More can be learned about the vertex of a quadratic function at https://brainly.com/question/24737967

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