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A projectile is launched with a velocity of 13.2 m/s at an angle of 37.0° above the horizontal.

How high above the point from which it was fired will the projectile be 1.0 s after firing?

a.
3.0 m


b.
12.8 m


c.
5.6 m


d.
13.2 m

Respuesta :

onyebuchinnaji

The height reached by the projectile from the point of projection is determined as 12.84 m.

Height reached by the projectile

H = vt + ¹/₂gt²

where;

  • v is vertical velocity
  • t is time of motion
  • g is acceleration due to gravity

H = (13.2 x sin37)(1) + (0.5)(9.8)(1)²

H = 12.84 m

Thus, the height reached by the projectile from the point of projection is determined as 12.84 m.

Learn more about height of projection here: https://brainly.com/question/20459093

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