Answer: See below
Explanation:
Given:
Mass of the Mercedes-Benz (m) = 1700 kg
Inclination of the road (θ) = 15.0
The free body diagram is shown in figure attached below
a) The normal force is equal to the cos component of the weight of the car.
[tex]\begin{aligned}&f=m g \cos \theta \\&f=1700 \times 9.81 \times \cos 15 \\&f=16108.74 \mathrm{~N}\end{aligned}[/tex]
b) The static force will be equal to the weight's sin component.
[tex]\begin{aligned}&f=m g \sin \theta \\&f=1700 \times 9.81 \times \sin 15 \\&f=4316.32 \mathrm{~N}\end{aligned}[/tex]
