The dimensions of the paper are 9 by 5 inches
Let x represent the length and y, the width
The given parameters are:
Perimeter, P = 28
Area, A = 45
So, we have
P = 2(x + y) = 28
A = xy = 45
Rewrite as:
2(x + y) = 28
xy = 45
By trial by error, we have:
x = 9 and y = 5
This can be proved as follows:
2(9 + 5) = 28--- true
9 * 5 = 45 --- true
Hence, the dimensions of the paper are 9 by 5 inches
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