Maximum Speed:
v = 0.9452ω
In SHM as we know that the velocity of the particle as function of displacement from mean position is :
v = ω √A² -x²
Now, substituting the values
v = ω √(0.953)² - (0.122)²
v = ω √ 0.908209- 0.014884
v = ω √0.893325
v = 0.9452ω
So, this is the maximum speed of the spring.
Learn more about SHM here:
https://brainly.com/question/16966751
#SPJ4