Answer:
a) 1/30
b) 1/6
Step-by-step explanation:
a) There are 10 people total and a group of 3 is being chosen. However, they all need to be women:
For the first person, the probability of it being a woman is 4/10
For the second person, the probability of it being a woman (with the prerequisite that the first was a woman) is 3/9
For the third (with the same requirements) is 2/8
If we multiply all of the fractions together, we get: [tex]\frac{1}{30}[/tex]
b) There are 10 people total and a group of 3 is being chosen. However, two of them need to be men, and 1 needs to be a woman:
For the first person, the probability of it being a man is 6/10
For the second person, the probability of it being a man (with the prerequisite that the first was a man as well) is 5/9
For the third person, the probability of it being a woman (because it can only be two men) is 4/8
If we multiply all the fractions together, we get: [tex]\frac{1}{6}[/tex]
