The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol. The element is S.
Hence, Option C is correct answer.
Ionization energy is the energy that an electron in a isolated gaseous atom or ion in the ground electronic state must absorb to discharge an electron resulting in a cation.
The third row element are Na, Mg, Al, Si, B, S, Cl, Ar
From the given options these elements belongs to third row Na, Mg, Al, Si, S, Cl, Ar.
Now check the first eight ionization energy of each element.
Na: 496, 4562, 6910, 9543, 13354, 16613, 20117, 25496 kJ/mol
Mg: 738, 1451, 7733, 10543, 13630, 18020, 21711, 25661 kJ/mol
Al: 578, 1817, 2745, 11577, 14842, 18379, 23326, 27465 kJ/mol
Si: 787, 1577, 3232, 4356, 16091, 19805, 23780, 29287 kJ/mol
S: 999.6, 2252, 3357, 4556, 7004, 8496, 27107, 31719 kJ/mol
Cl: 1251, 2298, 3822, 5159, 6542, 9362, 11018, 33604 kJ/mol
Ar: 1521, 2666, 3931, 5771, 7238, 8781, 11995, 13842 kJ/mol
Thus from the above conclusion we can say that The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol. The element is S.
Hence, Option C is correct answer.
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Question: The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol. Identify the element.
Choose One:
A. Mg
B. Cl
C. S
D. P
E. Al
F. Ar
G. Na
H. Si
