Respuesta :

Hello,

[tex]$\sum_{n=0}^4$(\frac{1}{2})^{n} =(-\frac{1}{2})^{0}+(-\frac{1}{2})^{1}+(-\frac{1}{2})^{2}+(-\frac{1}{2})^{3}+(-\frac{1}{2})^{4}=1-\frac{1}{2} +\frac{1}{4} -\frac{1}{8}+\frac{1}{16}[/tex]

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