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A driver jumped from a top of a 15-meter-high cliff down to the water below. if he moved with an initial horizontal velocity of 10m/s

a.) Find his Vx or horizontal Velocity

b.) Calculate the time it took him to reach the water

c.) How many meters will his range or horizontal displacement

Given:

Formula:

Solution:

Final Answer:
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Hi please help I need it bc I'm still confuse

Respuesta :

onyebuchinnaji

(a) The initial horizontal velocity of the driver is 10 m/s.

(b) The time taken for him to reach the water is 1.75 s.

(c) The horizontal displacement is 17.5 m.

Horizontal velocity of the driver (Vx)

The initial horizontal velocity of the driver is given as 10 m/s.

Time of motion of the driver

h = vy(t) + ¹/₂gt²

where;

  • vy is initial vertical velocity
  • t is time of motion
  • h is height of fall

h = 0 +  ¹/₂gt²

2h = gt²

t = √(2h/g)

t = √(2 x 15 / 9.8)

t = 1.75 s

Horizontal displacement of the driver

X = Vx(t)

X = 10 x 1.75

X = 17.5 m

Thus, the initial horizontal velocity of the driver is 10 m/s, the time of motion is 1.75 s and the horizontal displacement is 17.5 m.

Learn more about horizontal velocity here: https://brainly.com/question/24949996

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