The quadratic equation is y = 1/2x^2 - 3x + 4
How to determine the equation?
A quadratic equation is represented as:
y = ax^2 +bx + c
Using the values on the table, we have:
a(0)^2 + b(0) + c = 4 ---- when x = 0
a(2)^2 + b(2) + c = 0 ---- when x = 2
a(4)^2 + b(4) + c = 0 ---- when x = 4
Evaluate these equations
c = 4
4a + 2b + c = 0
16a + 4b + c = 0
Substitute c = 4
4a + 2b + 4 = 0
16a + 4b + 4 = 0
Divide through by 2 and 4
2a + b + 2 = 0
4a + b + 1 = 0
Subtract both equations
2a -1 = 0
Solve for a
a= 1/2
Substitute a= 1/2 in 4a + b + 1 = 0
4 * 1/2 + b + 1 = 0
Evaluate
2 + b + 1 = 0
Solve for b
b = -3
So, we have:
y = ax^2 +bx + c
This gives
y = 1/2x^2 - 3x + 4
Hence, the quadratic equation is y = 1/2x^2 - 3x + 4
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