Two children are riding on a merry-go-round. Child A is at a greater distance from the axis of rotation than child B. Which child has the larger tangential speed

Respuesta :

Answer: Two children are riding on a marry-go-round. Child A is at a greater distance from the axis of rotation than child B. Thus, the child A, located at a greater distance from the axis of rotation have a larger tangential speed.

Explanation: To find the correct answer we have to know more about the Angular velocity of a rotating body.

What is the angular velocity?

  • In rotational motion, the angular velocity ω can be defined as, the change in angular displacement(Ф) per unit time (t).
  • It's the revolution per second.
  • The angular velocity can be expressed in terms of the tangential velocity as well as the radius of the circular path as,

                              [tex]w=V/r[/tex]

How to solve the question?

  • We know that the expression for the tangential velocity as,

                               [tex]V=wr[/tex]

  • In the question, for both the child, the value of w will be same. Thus, the only quantity that depends on the tangential velocity will be the distance from the axis of rotation.
  • The maximum will the value of V, if the r maximizes.
  • Thus, child A with greater distance will have larger tangential speed.

Thus, we can conclude that, child A with greater distance will have larger tangential speed.

Learn more about the Angular velocity here:

https://brainly.com/question/28019892

#SPJ4