The p value is less, therefore one should reject the null hypothesis.
From the information given, the test statistic will be:
t = (10 - 0)/(6.733/✓7)
t = 3.930.
The degree of freedom will be:
= 7 - 1 = 6
Using the table, the p value will be 0.0039.
Since the p value is less than 0.05 one should reject the null hypothesis.
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