The slope of line AB, BC, CD and AD are 1, -1/6, 2, -4/6 respectively. Quadrilateral ABCD with the given vertices is not a parallelogram because neither pair of opposite sides is parallel. Option C
How to determine the slope
Formula for slope is given as;
Slope = [tex]\frac{y2 -y1}{x2 -x1}[/tex]
A(-4 -1)
B(-1 2)
C(5 1)
D(1 -3)
a. Slope of line AB = [tex]\frac{2- (-1)}{-1 (-4)}[/tex] = [tex]\frac{2+ 1}{-1 + 4}[/tex] = [tex]\frac{3}{3}[/tex] = 1
b. Slope of line BC = [tex]\frac{1-2}{5-(-1)}[/tex] = [tex]\frac{-1}{6}[/tex]
c. Slope of line CD = [tex]\frac{-3 - 5}{1-5}[/tex] = [tex]\frac{-8}{-4}[/tex] = 2
d. Slope of line AD = [tex]\frac{-3 (-1)}{1 -(-4)}[/tex] = [tex]\frac{-4}{5}[/tex]
Quadrilateral ABCD with the given vertices is not a parallelogram because neither pair of opposite sides is parallel. Option C
Thus, the slope of line AB, BC, CD and AD are 1, -1/6, 2, -4/6 respectively.
and quadrilateral ABCD with the given vertices is not a parallelogram because neither pair of opposite sides is parallel. Option C
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