A circular sheet of paper of radius 6 inches is cut into 3 equal sectors, and each sector is formed into a cone with no overlap. What is the height in inches of the cone

Respuesta :

The height of the cone is 4√2  inches.

The circumference of the base of each cone will be the arc length of one of the sectors  

= 2 [tex]\pi[/tex] (6)  / 3  

=  4 [tex]\pi[/tex]  inches

So, the radius, r, of each cone (in inches) is given  by :

4pi  =  2 [tex]\pi[/tex] * r

4  = 2r

2  = r  

Using the Pythagorean Theorem, the cone height, h, is given by :

h  = √[ slant height^2  - radius^2 ]  

=  √ [ 6^2  - 2^2 ]

= √32  

=  4√2  inches

In arithmetic, the Pythagorean theorem, or Pythagoras' theorem, is a essential relation in Euclidean geometry a few of the three facets of a right triangle. It states that the vicinity of the square whose facet is the hypotenuse is identical to the sum of the regions of the squares on the other two facets.

Learn more about Pythagorean theorem here https://brainly.com/question/343682

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