A 20.0 g sample of methyl alcohol (CH₃OH, molar mass 32.0 g/mol) was dissolved in 21.6 g of water. The mole fraction of CH₃OH is 0.342.
Number of moles = [tex]\frac{\text{Given Mass}}{\text{Molar Mass}}[/tex]
Number of moles of CH₃OH = [tex]\frac{20\ g}{32\ g/mol}[/tex]
= 0.625 mol
Number of moles of H₂O = [tex]\frac{21.6\ g}{18\ g/mol}}[/tex]
= 1.2 mol
Mole Fraction = [tex]\frac{\text{Moles of solute}}{\text{Moles of solute + Moles of solvent}}[/tex]
= [tex]\frac{0.625}{0.625 + 1.2}[/tex]
= [tex]\frac{0.625}{1.825}[/tex]
= 0.342
Thus from the above conclusion we can say that A 20.0 g sample of methyl alcohol (CH₃OH, molar mass 32.0 g/mol) was dissolved in 21.6 g of water. The mole fraction of CH₃OH is 0.342.
Learn more about the Mole Fraction here: https://brainly.com/question/14498215
#SPJ4
