Respuesta :

The nuclear binding energy per mole if the mass defect of a certain isotope is 0.1303 g per mol is [tex]3.909\times10^{7}\\[/tex]

What is the mass defect?

The difference between the total mass of a nucleus and the sum of the masses of all its constituent nucleons is known as the mass defect of the nucleus.

What is binding energy?

  • The binding energy (BE) of a nucleus is equal to the amount of energy released in forming the nucleus.
  • It is the mass defect multiplied by the speed of light squared.

              [tex]BE=\Delta mc^{2}[/tex]

Here,

The mass defect Δm is 0.1303g per mol

Therefore,

[tex]BE=\Delta mc^{2}\\BE=0.1303\times 3\times10^{8}\\BE=0.3909\times10^{8}\\BE=3.909\times10^{7}\\[/tex]

Hence, the nuclear binding energy per mole if the mass defect of a certain isotope is 0.1303 g per mol is [tex]3.909\times10^{7}\\[/tex]

Learn more about nuclear binding energy per mole is https://brainly.com/question/14265080

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