The speed (rate) of the plane in still air is 1100 kilometers per hour and the speed (rate) of the wind is 210 kilometers per hour.
We assume the speed (rate) of the plane in still air to be x kilometers per hour, and the speed (rate) of the wind to be y kilometers per hour.
Thus, flying against the wind, the acting speed (rate) for the plane will be x - y kilometers per hour.
Flying with the wind, the acting speed (rate) for the plane will be x + y kilometers per hour.
We are given that flying against the wind, the airplane travels 6230 kilometers in 7 hours.
Thus, speed (rate) = 6230/7 kilometers per hour = 890 kilometers per hour.
Equating this to the derived speed of the airplane flying against the wind, we get x - y = 890 ... (i).
We are given that flying with the wind, the airplane travels 10480 kilometers in 8 hours.
Thus, speed (rate) = 10480/8 kilometers per hour = 1310 kilometers per hour.
Equating this to the derived speed of the airplane flying with the wind, we get x + y = 1310 ... (i).
Now, on adding equations (i) and (ii), we get:
2x = 2200,
or, x = 1100.
Substituting x = 1100 in (ii), we get:
x + y = 1310,
or, 1100 + y = 1310,
or, y = 1310 - 1100 = 210.
Thus, the speed (rate) of the plane in still air is 1100 kilometers per hour and the speed (rate) of the wind is 210 kilometers per hour.
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