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The friction force between the box and the incline if the box does not slide down the incline will be 0.577
The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction. There are several kinds of friction: Two solid surfaces in touch are opposed to one another's relative lateral motion by dry friction.
Given the box resting on the inclined plane above has a mass of 20kg and the The incline sits at a 30 degree angle
We have to find the friction force between the box and the incline if the box does not slide down the incline
Since the frictional force F₁ must equal or exceed gravitational force F₂ down the incline:
F₁ = F₂
μmgcosΘ = mgsinΘ
μ = (mgsinΘ)/(mgcosΘ)
μ = tanΘ
μ = 0.577
Hence the friction force between the box and the incline if the box does not slide down the incline will be 0.577
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:The resistance created by the box's friction with the incline The slope will be 0.577 if the box doesn't descend.
Friction is the force that prevents solid surfaces, fluid layers, and material constituents from sliding past one another. Different types of friction exist. Dry friction opposes the relative lateral motion of two touching solid surfaces.
Given that the 20-kg box lying on the inclined plane above and the incline's 30 degree inclination
If the box does not slide down the incline, we must determine the friction force between them.
Given that the gravitational force F2 down the gradient must be equal to or greater than the frictional force F1,
F₁ = F₂
If mgcosx = mgsinx
equals (mgsinx)/(mgcosx)
μ = tanx
μ = 0.577
Therefore, if the box does not slide down the incline, the friction force between the box and the incline will be 0.577.
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