The magnitude of the electrical force acting between both the given charges which are separated by 0.008 m is 6.07 N.
Given Charges 2.4*[tex]10^{-8} C[/tex] and 1.8 *[tex]10^{-6} C[/tex] that are separated by 0.008 m.
We have to find the magnitude of the electrical force acting between the charges. Magnitude is the property which determines the size of an object or process. Force is an influence that can change the direction of an object.
To find the magnitude we have to use Coulomb's law which says that
[tex]F_{E}=K*(q_{1}*q_{2}/d^{2}[/tex]
where K is Coulomb's constant whose value is [tex]8.9910^{9}Nm^{2} C^{2}[/tex].
[tex]q_{1}[/tex]=[tex]2.6*10^{-8} C[/tex] and
[tex]q_{2}=1.8*10^{-6} C[/tex] are the electric charges.
d=0.008m is the separation distance between the charges.
Putting the values in the given formula we get:
[tex]F_{E} =8.99(10)^{9}Nm^{2}/C^{2} *(2.4(10)^{-8}C(1.8(10)^{-6}C)/(0.008m)^{2}[/tex]
=6.07 N
Hence the magnitude of force acting between [tex]2.4*10^{-8} C[/tex] and [tex]1.8*10^{-6}C[/tex] is 6.07 N.
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