The change in the internal energy of the system is increased by 1 Kj.
According to the first law of thermodynamics,
Therefore, Δ∪=q+w
[Δ∪= change of internal energy; q=heat; w=work]
Provided,
q= -3Kj (as heat is given away)
w= +2Kj (work done in the system is positive)
So, Δ∪= -3 + (+2) Kj
⇒Δ∪= -1 Kj
Therefore the internal energy of the system is increased by 1 kj.
Learn more about thermodynamics here:
https://brainly.com/question/1368306
#SPJ4