I’m having issues with finding the restriction of the equation in the photo
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Answer:
x = 9
Step-by-step explanation:
[tex]\sf \dfrac{(x +7)(x+8)}{(x -9(x + 6)} \ \div \ \dfrac{(x+8)(x - 2)}{(x+ 6)(x - 2)} =\dfrac{(x +7)(x+8)}{(x -9)*(x +6)}*\dfrac{(x + 6)(x - 2)}{(x +8 )(x - 2)}[/tex]
[tex]\sf =\dfrac{x +7}{x - 9}[/tex]
x - 9 = 0
x = 9
If we plugin x = 9, then the denominator would become 0 and hence the expression will become undefined.
So, x = 9 is the restricted value of the expression.