The revolution is greater than the Rotation.
In this equation, the letter "r" represents the radius of Mars. Therefore, we can substitute the values in the equation as follows:
[tex]2*3.14*(3.4*10^6)= 21.36*10^6m[/tex]
As seen in the question, Mars spends 24 hours and 37 minutes. If we consider that 1 minute has 60 seconds, we can multiply 37 by 60 and we will find that in 37 minutes there are 2,220 seconds.
We must also consider that 1 hour has 60 minutes. So if we multiply 24 by 60, we know that in 24 hours we have 1,440 minutes. If we multiply this value of minutes by 60, we will find that they represent 86,400 seconds.
In this case, we must add the two values of seconds, and thus we will find that 88.620 seconds are spent in 24 hours and 37 minutes.
With this, we can calculate the Tangential speed of Mars' rotation as follows:
Mars rotation/seconds spent rotating =
[tex]\frac{21.36*10^6}{88,620} = 241.02\frac{m}{s}[/tex]
In this equation, the letter "d" represents the distance between Mars and the Sun. Therefore, we can substitute the values in the equation as follows: [tex]2*3.14*(2.3*10^1^1) = 1.45*10^1^2m[/tex]
We know that Mars spends 687 days to achieve this. We also know that 1 day has 24 hours which corresponds to 86,400 seconds. Therefore, we must multiply 86,400 seconds by 687 days to get the result equal to 59,356,800 seconds spent for Mars to complete its rotation around the sun.
After that, we can calculate the Tangential speed of Mars' revolution as follows:
Mars' revolution around Sun / seconds spent to complete revolution =
[tex]\frac{1.45*10^1^2}{59,356,800} = 24.42*10^3\frac{m}{s}[/tex]
Learn more about calculating Mars' Rotation and Revolution:
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