Please help!! Find the solution for t in the equation:

Answer:
t = 1.322
Step-by-step explanation:
4×(2^t) = 10
2^t = 10/4 = 2.5
t = log2(2.5)
now, the logarithm to the base 2 of 2.5 must be larger than 1, as 2.5 is larger than 2.
so, it can be only the 4th answer option.
now, to actually calculate it :
log2(2.5) = log10(2.5) / log10(2) = 1.321928095... ≈
≈ 1.322
we were correct.
Answer:
t = 1.322
Step-by-step explanation:
Given equation:
[tex]4(2^t)=10[/tex]
Divide both sides by 4:
[tex]\implies \dfrac{4(2^t)}{4}=\dfrac{10}{4}[/tex]
[tex]\implies 2^t=2.5[/tex]
Take natural logs of both sides:
[tex]\implies \ln 2^t = \ln 2.5[/tex]
[tex]\textsf{Apply the natural log power law}: \quad \ln x^n=n \ln x[/tex]
[tex]\implies t \ln 2 = \ln 2.5[/tex]
Divide both sides by ln 2:
[tex]\implies \dfrac{t \ln 2}{\ln 2} = \dfrac{\ln 2.5}{\ln 2}[/tex]
[tex]\implies t= \dfrac{\ln 2.5}{\ln 2}[/tex]
[tex]\implies t=1.321928095...[/tex]
[tex]\textsf{Apply log law}: \quad a^c=b \iff \log_ab=c[/tex]
[tex]\implies \log 2 (2.5)=t[/tex]
[tex]\implies t=1.321928095...[/tex]
Therefore, the solution that is nearest to the exact solution is t = 1.322