The percentage composition of Nitrogen in the compound is 35.71%
Using the ideal gas equation, the mole of nitrogen can be obtained as follow
PV = nRT
n = PV / RT
n = (700 × 0.1) / ( 62.364 × 250)
n = 0.00448 mole
Mass = mole × molar mass
Mass of nitrogen = 0.00448 × 28
Mass of nitrogen = 0.125 g
Percentage = (mass of element / mass of compound) × 100
Percentage of nitrogen = (0.125 / 0.35) × 100
Percentage of nitrogen = 35.71%
Learn more about mass composition:
https://brainly.com/question/11617445
#SPJ1