0.350g of an organic compound gave 100ml of Nitrogen collected at
250K temperature and 700mm pressure. Calculate the percentage
composition of Nitrogen in the compound.
Use Dumas method​

Respuesta :

The percentage composition of Nitrogen in the compound is 35.71%

How to determine the mole of nitrogen

  • Volume (V) = 100 mL = 100 / 1000 = 0.1 L
  • Pressure (P) = 700 mmHg
  • Temperature (T) = 250 K
  • Gas constant (R) = 62.364 torr.L/Kmol
  • Number of mole (n) =?

Using the ideal gas equation, the mole of nitrogen can be obtained as follow

PV = nRT

n = PV / RT

n = (700 × 0.1) / ( 62.364 × 250)

n = 0.00448 mole

How to determine the mass of nitrogen

  • Mole of nitrogen = 0.00448 mole
  • Molar mass of nitrogen = 28 g/mol
  • Mass of nitrogen = ?

Mass = mole × molar mass

Mass of nitrogen = 0.00448 × 28

Mass of nitrogen = 0.125 g

How to determine the percentage of nitrogen

  • Mass of nitrogen = 0.125 g
  • Mass of compound = 0.35 g
  • Percentage of nitrogen =?

Percentage = (mass of element / mass of compound) × 100

Percentage of nitrogen = (0.125 / 0.35) × 100

Percentage of nitrogen = 35.71%

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