Which of the following options is a polynomial with a root 2i and exactly 2
real roots?
A. F(x)=x²-x²³ +2x² - 4x-8
B. F(x)=x²-x² + 4x-4
C. F(x)=x²-x³-6x² +4x+8
OD. F(x)= x³ + x² + 4x+8

Respuesta :

The polynomial with a root 2i and exactly 2 real roots is F(x)=x³-x² + 4x-4

Factorizing polynomial functions

Given the polynomial function below

F(x)=x³-x² + 4x-4

Group

F(x)=(x³-x²) + (4x-4)

f(x) = x²(x-1)+4(x-1)

f(x) = (x²+4)(x-1)

If f(x) = 0

x²+4 = 0 and x -1. = 0

x² = -4 and x = 1

x = ±2i and -1

Hence polynomial with a root 2i and exactly 2 real roots is F(x)=x³-x² + 4x-4

Learn more on zeros of polynomial here: https://brainly.com/question/11724515

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