Answer:
= 1.03 x 10⁻² g H₂O
Explanation:
To find the mass of water, you need to (1) convert grams CH₄ to moles CH₄ (via molar mass), then (2) convert moles CH₄ to moles H₂O (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles H₂O to grams H₂O (via molar mass). The final answer should have 3 sig figs to reflect the given value (4.60 x 10⁻³ g).
Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)
Molar Mass (CH₄): 16.043 g/mol
Combustion of Methane:
1 CH₄ + 2 O₂ ---> 2 H₂O + 1 CO₂
Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol
Molar Mass (H₂O): 18.014 g/mol
4.60 x 10⁻³ g CH₄ 1 mole 2 moles H₂O 18.014 g
-------------------------- x ----------------- x --------------------- x ---------------- =
16.043 g 1 mole CH₄ 1 mole
= 0.0103 g H₂O
= 1.03 x 10⁻² g H₂O
