The total number of :
(a) p electrons in n (z=7) is 3
(b) s electrons in si (z=14) is 6
(c) 3d electrons in s (z=16) is 0
Electronic configuration:
The distribution of electrons in an element's atomic orbitals is described by the element's electron configuration. Atomic electron configurations adhere to a standard nomenclature in which all atomic subshells that contain electrons are arranged in a sequence with the number of electrons they each hold expressed in superscript.
The electronic configuration of z=7 (nitrogen) is 1s²2s²2p³
Total number of p electrons = 3
The electronic configuration of z=14 (silicon) is 1s²2s²2p⁶3s²3p²
Total number of s electrons = 2+2+2=6
The electronic configuration of z=16 (sulphur) is 1s²2s²2p⁶3s²3p⁴
Total number of 3d electrons = 0
Learn more about electronic configuration here:
https://brainly.com/question/14283892
#SPJ4