the action-reaction forces that the blocks exert on each other will 13 N and 22N
Force on a Horizontal Plane
Force is the product of mass and acceleration. There will be constant acceleration on both object X and Y.
Given that the Mass of block X is 10 kg and that of block Y is 5 kg. The magnitude of force of friction on blocks X and Y is 8.0 N and 4.0 N respectively. if an applied force of 40 N [right] acts on block,
We are given that:
- Magnitude of friction on X block = 8N
- Magnitude of friction on Y block = 4 N
With the use of the formula below,
F - [tex]F_{r}[/tex] = ma
Where
- [tex]F_{r}[/tex] = frictional force
The acceleration will be;
40 - (8 + 4) = (10 + 5)a
40 - 12 = 15 a
28 = 15a
a = 28/15
a = 1.8667 m/[tex]s^{2}[/tex]
The tension between the two blocks will be
Force applied-frictional force on X-tension = mass of X × acceleration
That is,
F - [tex]F_{r}[/tex] = ma
40-8-T = 10 × 1.8667
32 - T = 18.667
T = 32 - 18.667
T = 13.33 N
The opposite reaction will be
F - 8 = 10 x 1.8667
F - 4 = 18.67
F = 18.67 + 4
F = 22.67 N
Therefore, the action-reaction forces that the blocks exert on each other will 13 N and 22N
Learn more about forces here: https://brainly.com/question/388851
#SPJ1
